Mixing colors | Add 10 percent of one color to another | ActionScript 3.0 AS3
Published by Nicholas Dunbar on December 24th, 2012
If you want to add one color to another and then set a movie clip to that tint I have provided the function below. The idea is to sort of mix colors in the way paint is mixed here is how you do it:
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//requires the RGB class which can be found at the following link: | |
//https://gist.github.com/nicholasdunbar/8812643 | |
//layerToTint.transform.colorTransform has to initialized to some color before this will work. | |
function addColorToLayer(layerToTint:DisplayObject, hexVal:String):void{ | |
var colorTransform:ColorTransform = new ColorTransform(); | |
var newColor:uint; | |
var rgb:RGB = new RGB(); | |
var rgb2:RGB = new RGB(); | |
var rgb3:RGB = new RGB(); | |
rgb.r = parseInt( "0x"+hexVal.charAt(0)+hexVal.charAt(1) ); | |
rgb.g = parseInt( "0x"+hexVal.charAt(2)+hexVal.charAt(3) ); | |
rgb.b = parseInt( "0x"+hexVal.charAt(4)+hexVal.charAt(5) ); | |
rgb2.r = layerToTint.transform.colorTransform.redOffset; | |
rgb2.g = layerToTint.transform.colorTransform.greenOffset; | |
rgb2.b = layerToTint.transform.colorTransform.blueOffset; | |
rgb3.r = int( (rgb.r*.1)+(rgb2.r*.9) ); | |
rgb3.g = int( (rgb.g*.1)+(rgb2.g*.9) ); | |
rgb3.b = int( (rgb.b*.1)+(rgb2.b*.9) ); | |
// convert the new number to a hex and then an int and transform the mc | |
newColor = (rgb3.r << 16) | (rgb3.g << 8) | rgb3.b; | |
layerToTint.changeColor(newColor); | |
} | |
//for more information on this function http://www.actionscript-flash-guru.com/blog/37-mixing-colors-add-10-percent-of-one-color-to-another-actionscript-30-as3-.php | |
//for more information on the RGB class see http://www.actionscript-flash-guru.com/blog/36-uint-to-6-digit-rgb-hex-actionscript-30-as3.php |
Check out the RGB class here:
[converting RGB to 6 digit hexadecimal format.](http://www.actionscript-flash-guru.com/blog/36-uint-to-6-digit-rgb-hex-actionscript-30-as3)
layerToTint.transform.colorTransform has to initialized to some color before this will work.